2x^2-x-300=0

Solution for 2x^2-x-300=0 equation:

2x^2-x-300=0

We add all the numbers together, and all the variables

2x^2-1x-300=0

a = 2; b = -1; c = -300;
Δ = b2-4ac
Δ = -12-4·2·(-300)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-49}{2*2}=\frac{-48}{4}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+49}{2*2}=\frac{50}{4}
=12+1/2
$